The force in the situation without a mass in the center (but rather next to it, to the side) will still have that net-zero in the center, but the force comes out immediately next to it.

Wind force on planet Earth shows us this already. The Eye is without wind force, and yet created by wind force. This force expresses itself (to the max) with the Wall of the Eye.

So, the model is like this:

0, 1, 0.9, 0.8, 0.7, 0.4, 0.2, etcetera.

The Wall is the strongest expression when a force does not have a mass in its center but rather is located to the side of it.

The binary star system's center will not show us too much expression of that Wall since there are 'just' two stars.

The greater the number of stars in a system, the stronger the force expressed in the center.

Here is something to gnaw on for you that involves force:

When we have a tug-of-war, the tension on the rope goes toward the winner.

Now, consider there are 10,000 groups with 5,000 ropes in between them, and all these ropes crossing one another via the central part of all these ropes. Then, with all that pushing and pulling, the ropes will get entangled, and the surprise is then that the center will end up empty of rope.

What will happen is a large circle of ropes will get built around the center, and no rope would be crossing the center any longer.

I am not sure if you have the ability to envision this. You tend to reject the analogy tools I provide you.

--

Remember, we are talking force here.

A force can be associated right with the mass itself, or with the interplay of force of several masses, none of them circling a central mass.